The 6K Series Language allows you to store binary numbers(32-bit or less) in the binary variable(VARB) command. The binary variables start at the left with least significant bit, and increase to the right. The 32-bit binary value must be in the form of ones,zeros,or Xs. The information is assigned to the binary variable with the equal sign.
Example: VARB1 = b1001
This will set VARB1 to the binary value 1001. Please note that a b is required.
If the variable is querried (by typing VARB1 at the prompt in the terminal) the response will be:
*VARB1=1001_xxxx_xxxx_xxxx_xxxx_xxxx_xxxx_xxxx.
You can change one bit within any binary variable by using the following covention:
VARB1.6-1
This will set bit 6 of varb1 to 1. Any bit can be assigned the values of 1, 0, or X.
NOTE:Compumotor doccumentation states that an X used on the right side of an assignment statement will leave that particular bit unaffected. THIS IN NOT CORRECT.
Example: VARB1=b1101XX1
This will set binary variable 1 to 1101XX1. THIS ASSIGNS THE VALUE XX TO BITS 5&6 AND DOES NOT LEAVE BIT 5&6 IN THEIR PREVIOUS STATE.
Binary variables are also used in conjunction with bitwise operators and(&), inclusive or(|), exclusive or(^), and Not(~)
Example:
VARB1=b10010110
VARB2=b01101010
VARB3=VARB1&VARB2
VARB3 Response *varb3=0000_00010_XXXX_XXXX_XXXX_XXXX_XXXX_XXXX
VARB3=VARB1|VARB2
VARB3 Response *VARB3=1111_1110_XXXX_XXXX_XXXX_XXXX_XXXX_XXXX
The following is a truth table for the Boolean Operators.
a b a&b a|b a^b 1 1 1 1 0 1 0 0 1 1 0 1 0 1 1 0 0 0 0 0 x x x x x 1 x x 1 x x 1 x 1 x 0 x 0 x x x 0 0 x x
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